G99
T0707
G00 X35 Z2
#1 = 0
WHILE[#1 LE 47.16] DO 1
#2 = 30*SQRT[1-[[#1/2]*[#1/2]]/[24*24]]
G01 X[#1] Z[#2]
#1 = #1+0.12
END 1
T0707
G0 X35 Z100
M30
O8002(橢圓弧)
G99
T0707
G00 X35 Z2
#23 = 50;X
#24 = 56;Z
#26 = -20
#100 = 50
WHILE[#100 GE 24] DO 2
#123 = #23
#124 = #24
#27 =[#24*#24]
#28 =[#24]
WHILE[#24 GE #26] DO 1
#1 = #23*SQRT[1-[#24*#24]/#27]
G01 X#1 Z[#24-60] F0.1
#24 = #24-1
END 1
#23 = #123-1
#24 = #124-1
#100 = #100-1
END 2
T0707
G0 X35 Z100
M30
兩個宏程序妳自己研究吧
可以去看看視頻（橢圓宏程序）