#include?<string.h>
#include?<ctype.h>
#include?<stdlib.h>
#define?MAX_LONG?5?//?假設只有5個數字
void?main(void)
{
unsigned?int?digits[100];
char?target[]="70112";?//?這裏是妳的目標數字(當然妳也可改為其它的5個數字)
char?dest[12];
int?start=-1,i,j,k,len,sum,OddNumber,EvenNumber;
i=j=k=len=OddNumber=EvenNumber=sum=0;
while?(target[i])
{
start=i;
len=1;
strncpy(dest,&target[start],len);
dest[len]='\0';
digits[j]=atoi(dest);
j++;
start=-1;
i++;
}
for?(k=0;k<MAX_LONG;k++)
{
sum+=digits[k];?//5數之和
if(digits[k]%2==0)?EvenNumber+=digits[k];?//?偶數求和
else?OddNumber+=digits[k];?//?奇數求和
}
printf("五數之和:%d\n奇數之和:%d\n偶數之和:%d\n",sum,OddNumber,EvenNumber);
}