第壹題:
#include?<stdio.h>long?fun(int?n)?{?//?計算1到n?所有數的乘積?1?*?2?*?3?*...n
long?fac=?1;
int?i;?
for?(i?=?1;?i?<=?n;?i?++)?{
fac?*=?i;
}?
return?fac;?
}?
int?main(void)?{
int?i;?
long?sum?=?0;
for?(i?=?1;?i?<?4;?i?+=?2)?{?//?循環?2次?i?=?1?3
sum?=?sum?+?fun(i);
}?
printf("sum=%ld\n",?sum);?
return?0;
}
第二題:
#include?<stdio.h>? //?元素首位交換位置void?fun(int?x[],?int?n)?{?
int?i,?j,?temp;
i?=?0;?j?=?n?-?1;?
while?(i?<?j)?{
temp?=?x[i];
x[i]?=?x[j];
x[j]?=?temp;
i?++;
j?--;
}
}
int?main(void)?{
int?x[]?=?{1,?2,?3,?4,?5,?6};?
fun(x,?6);?
for?(int?i?=?0;?i?<?6;?i?++)?{?
printf("%2d",?x[i]);
}
//?運行結果?6?5?4?3?2?1
return?0;
}
第三題:
#include?<stdio.h>double?fun(double?x[3][4])?{
int?i,?j;?
double?sum?=?0;
for?(i?=?0;?i?<?3;?i?++)?{?
for?(j?=?0;?j?<?4;?j?++)?{?
sum?=?sum?+?x[i][j];
}?
}?
return?sum?/?12;?
}
int?main(void)?{?
double?x[3][4]?=?{{1.2,?3.1},?{6.5},?{2.6,?8.9}},?ave;?
ave?=?fun(x);
printf("ave=%lf\n",?ave);?
return?0;?
}