2. if判斷是否結束
3. 遍歷數組
import java.util.Arrays;
import java.util.Scanner;
public class ShuZu{
public static void main(String[] args) {
int a = 0;
int[] aa= new int[0];
Scanner cin = new Scanner(System.in);
for(;;){
System.out.println("請輸入10以內的整數，-1表示結束");
String s1 = cin.nextLine();
try{
a = Integer.parseInt(s1);
//a = cin.nextInt();
if(a == -1){
cout(aa);
break;
}
else if(a>=0 && a<=10){
if(aa.length == 0)
aa = new int[]{a};
else{
aa = Arrays.copyOf(aa, aa.length+1);//因為要求用數組，否則直接String簡單些
aa[aa.length-1] = a;
}
}
else
System.out.println("請輸入10以內的整數");
}catch(Exception e){
System.out.println("您輸入的不是數字，請重新輸入");
}
System.out.println(Arrays.toString(aa));
}
}
private static void cout(int[] aa) {
int tem = 0;
outer:
for(int i=0;i<aa.length;i++){
int count = 1;
tem = aa[i];
for(int j=0;j<i;j++){
if(tem == aa[j]){
continue outer;
}
}
for(int j=i+1;j<aa.length;j++){
if(tem == aa[j]){
count++;
}
}
System.out.println(tem +"\t次數："+ count);
}
}
}