linux下，編寫壹個c語言程序實現...（詳細見正文）！急！200分懸賞！

參考ln -l命令的輸出結果，編寫了以下程序（即輸出結果和ls -l命令的輸出結果相似），通過命令行傳入要查看的目錄，如果沒有傳入參數，則顯出當前目錄：

#include <unistd.h>

#include <sys/stat.h>

#include <sys/types.h>

#include <dirent.h>

#include <stdio.h>

#include <string.h>

#include <stdlib.h>

#include <pwd.h>

#include <time.h>

char *getmod(mode_t mode,char *line) /*生成權限描述字符串*/

{

memset(line,0,sizeof(char)*11);

strcat(line,S_ISDIR(mode)?"d":"-");

strcat(line,(mode&S_IRWXU)&S_IRUSR?"r":"-");

strcat(line,(mode&S_IRWXU)&S_IWUSR?"w":"-");

strcat(line,(mode&S_IRWXU)&S_IXUSR?"x":"-");

strcat(line,(mode&S_IRWXG)&S_IRGRP?"r":"-");

strcat(line,(mode&S_IRWXG)&S_IWGRP?"w":"-");

strcat(line,(mode&S_IRWXG)&S_IXGRP?"x":"-");

strcat(line,(mode&S_IRWXO)&S_IROTH?"r":"-");

strcat(line,(mode&S_IRWXO)&S_IWOTH?"w":"-");

strcat(line,(mode&S_IRWXO)&S_IXOTH?"x":"-");

return line;

}

char *directory(char *argv) /*從程序參數取出目錄*/

{

int i;

for (i=strlen(argv)-1;i;--i)

if (argv[i]=='/'){

argv[i+1]='\0';

break;

}

return argv;

}

int main(int argc,char *argv[])

{

DIR *dirp;

struct dirent *dirst;

struct stat finfo;

char *path,fname[512],mod[11],ctm[10];

struct passwd *user=NULL;

struct tm *ltm;

if (argc==1) path=directory(argv[0]);

else path=argv[1];

dirp=opendir(path);

if (!dirp)

{

fprintf(stderr,"ERROR\n");

exit(-1);

}

for (dirst=readdir(dirp);dirst;dirst=readdir(dirp))

{

strcpy(fname,path);

lstat(strcat(strcat(fname,"/"),dirst->d_name),&finfo);

user=getpwuid(finfo.st_uid);

printf("%s\t%10s\t",getmod(finfo.st_mode,mod),user->pw_name);

printf("%10d\t%9d\t",finfo.st_ino,finfo.st_size);

ltm=localtime(&finfo.st_mtime);

strftime(ctm,9,"%b",ltm);

printf("%5s",ctm);

strftime(ctm,9,"%d",ltm);

printf("%3s",ctm);

strftime(ctm,9,"%Y",ltm);

printf("%5s\t",ctm);

printf("%s\n",dirst->d_name);

}

closedir(dirp);

return 0;

}

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