如何在不同編程語言中獲取現在的Unix時間戳

如何在不同編程語言中獲取現在的Unix時間戳(Unix timestamp)？

先上代碼進行java時間轉換成unix timestamp

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import java.text.DateFormat;

import java.text.ParseException;

import java.text.SimpleDateFormat;

import java.util.Date;

/**

* @author kongqz kongqingzhu@gmail.com

* @version 創建時間：2013-2-19 上午10:21:47

*/

public class TestUnixTime {

public static void main(String[] args) throws ParseException{

DateFormat df=new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

//1361325960

long epoch = df.parse("2013-02-20 10:06:00").getTime();

System.out.println("should be 1361325960 ："+epoch);

Date d=new Date();

String t=df.format(d);

epoch=df.parse(t).getTime()/1000;

System.out.println("t is ："+t+",unix stamp is "+epoch);

}

}

Java time

JavaScript Math.round(new Date().getTime()/1000)

getTime()返回數值的單位是毫秒

Microsoft .NET / C# epoch = (DateTime.Now.ToUniversalTime().Ticks - 621355968000000000) / 10000000

MySQL SELECT unix_timestamp(now())

Perl time

PHP time()

PostgreSQL SELECT extract(epoch FROM now())

Python 先 import time 然後 time.time()

Ruby 獲取Unix時間戳：Time.now 或 Time.new

顯示Unix時間戳：Time.now.to_i

SQL Server SELECT DATEDIFF(s, '1970-01-01 00:00:00', GETUTCDATE())

Unix / Linux date +%s

VBScript / ASP DateDiff("s", "01/01/1970 00:00:00", Now())

其他操作系統

(如果Perl被安裝在系統中) 命令行狀態：perl -e "print time"

如何在不同編程語言中實現Unix時間戳(Unix timestamp) → 普通時間？

Java String date = new java.text.SimpleDateFormat("dd/MM/yyyy HH:mm:ss").format(new java.util.Date(Unix timestamp * 1000)).getTime();

JavaScript 先 var unixTimestamp = new Date(Unix timestamp * 1000)然後 commonTime = unixTimestamp.toLocaleString()

Linux date -d @Unix timestamp

MySQL from_unixtime(Unix timestamp)

Perl 先 my $time = Unix timestamp 然後 my ($sec, $min, $hour, $day, $month, $year) = (localtime($time))[0,1,2,3,4,5,6]

PHP date('r', Unix timestamp)

PostgreSQL SELECT TIMESTAMP WITH TIME ZONE 'epoch' + Unix timestamp) * INTERVAL '1 second';

Python 先 import time 然後 time.gmtime(Unix timestamp)

Ruby Time.at(Unix timestamp)

SQL Server DATEADD(s, Unix timestamp, '1970-01-01 00:00:00')

VBScript / ASP DateAdd("s", Unix timestamp, "01/01/1970 00:00:00")

其他操作系統

(如果Perl被安裝在系統中) 命令行狀態：perl -e "print scalar(localtime(Unix timestamp))"

如何在不同編程語言中實現普通時間 → Unix時間戳(Unix timestamp)？

Java long epoch = new java.text.SimpleDateFormat("dd/MM/yyyy HH:mm:ss").parse("01/01/1970 01:00:00");

JavaScript var commonTime = new Date(Date.UTC(year, month - 1,day,hour,minute,second))

MySQL SELECT unix_timestamp(time)

時間格式: YYYY-MM-DD HH:MM:SS 或 YYMMDD 或 YYYYMMDD

Perl 先 use Time::Local 然後 my $time = timelocal($sec, $min, $hour, $day, $month, $year);

PHP mktime(hour, minute, second, day,month,year)

PostgreSQL SELECT extract(epoch FROM date('YYYY-MM-DD HH:MM:SS'));

Python 先 import time 然後 int(time.mktime(time.strptime('YYYY-MM-DD HH:MM:SS', '%Y-%m-%d %H:%M:%S')))

Ruby Time.local(year, month, day, hour,minute,second)

SQL Server SELECT DATEDIFF(s, '1970-01-01 00:00:00', time)

Unix / Linux date +%s -d"Jan 1, 1970 00:00:01"

VBScript / ASP DateDiff("s", "01/01/1970 00:00:00", time)

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