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lingo達人幫忙分析下下面哪裏有語法錯誤啊 大謝~~OK後必有厚報~~^_^

妳的amy集是什麽 只有壹個元素還定義個集 不是找麻煩嗎

model:

sets:

amy/1/;

ig/1..3/;

jc/1..5/;

ns/1..8/;

kw/1..10/;

xx(ig,jc,kw):x; !未知量X3,5,8;

yy(jc,ns,kw):y; !未知量Y5,8,10;

ab(ig,kw):a,b; !年產量和訂購單價矩陣3,10;

cc(ig,jc):cg; !運輸價格3,5;

save(amy,kw):v,m; !10種物資的體積和單件庫存費;

ff(jc,ns):f; !運輸價格5,8;

ee(ns,kw):e; !需求量8,10;

cw(jc,kw):p; !5個倉庫的10種物品5,10;

endsets

data:

a=2000 30000 3000 1000 3200 1000 300000 2000 1500 1500

2000 1300 300000 1000 200000 1500 2000 1500 200000 1200

200000 2500 800 1500 200000 1000 1400 200000 2500 1500;

b=100 10000 210 250 290 300 20000 430 450 500

90 180 20000 240 20000 305 380 435 30000 490

20000 170 210 245 20000 285 400 30000 450 480;

cg=2000 10 14 17 13

10 8 2000 9 16

15 16 9 15 2000;

v=1.5 1 1.5 2 1.5 0.5 1.5 2 1 0.5;

m=40 70 90 100 120 120 150 160 180 200;

f=3 2 3 6 3 1 4 5

1000 3 3 1000 5 2 5 3

5 1000 2 5 1000 5 1000 4

4 1 4 4 2 1000 2 1000

2 2 5 3 5 2 5 2;

e=60 300 800 100 200 600 400 80 150 600

90 800 500 1200 500 400 200 100 800 500

150 500 400 800 600 100000 800 800 400 100000

300 400 200 400 150 800 500 150 1500 400

400 100000 150 100 200 300 100000 400 90 800

500 200 1000 100000 400 150 1000 1000 200 400

800 1200 90 150 90 1000 90 500 100 1000

1500 200 500 500 1000 90 150 200 500 200;

enddata

min=!工廠購貨;@sum(ab(I,K):b(I,K)*(@sum(jc(J):x(I,J,K))))+!

A-B運輸費用;@sum(cc(I,J):cg(I,J)*(@sum(kw(k):x(I,J,K))))+!

儲存費用;@sum(amy(K):m(1,K)*@sum(jc(J):@sum(ig(I):x(I,J,K))))+!

B-C運輸費用;@sum(ff(J,N):f(J,N)*@sum(kw(K):y(J,N,K)))+!

缺貨費;2*@sum(amy(K):m(1,K)*@sum(ns(N):e(N,K)))-2*@sum(amy(K):m(1,K)*@sum(ns(N):@sum(jc(J):y(J,N,K))));

@for(ab(I,K):(@sum(jc(J):x(I,J,K)))<=a(I,K)); !訂購量小於年產量;

@sum(amy(k):v(1,K)*@sum(ig(I):x(I,1,K)))<=800; !倉庫的庫容限制;

@sum(amy(k):v(1,K)*@sum(ig(I):x(I,2,K)))<=600;

@sum(amy(k):v(1,K)*@sum(ig(I):x(I,3,K)))<=1000;

@sum(amy(k):v(1,K)*@sum(ig(I):x(I,4,K)))<=700;

@sum(amy(k):v(1,K)*@sum(ig(I):x(I,5,K)))<=800;

@for(cw(J,K):@sum(ig(I):x(I,J,K))=@sum(ns(N):y(J,N,K))); !倉庫的貨都運到商店了,對應相等;

@for(ee(N,K):e(N,K)>=@sum(jc(J):y(J,N,K))); !到貨的數量小於等於需求量;

@for(xx(I,J,K):@gin(x(I,J,K))); !定義為整數;

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