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#include<stdio.h>
#define N 10
int main()
{
int i,count=0,a[N]={66,33,77,22,88,56,73,89,34,67};
float bujige=0;
for (i=0;i<N;i++)
{
if ( a[i] < 60)
{
count++;
}
}
bujige = ((float)count/N)*100;
printf("有%d個學生不及格,不及格率為:%-5.2f%%。\n",count,bujige);
return 0;
}