# include & ltmath.h & gt
主()
{
int n[9]={1,2,3,4,5,6,7,8,9 };
int I;
float sum = 0;
for(I = 0;我& lt8;i++)
sum+= sqare((n[I]+n[I+1])/2.0);
printf("sum=%d ",sum);
getchar();
}