C++函數編程，如果壹個整數逆序後得到的數值和原數值相同，則稱之為幸運數。輸入壹個整數N

#include<string>

#include<algorithm>

using?namespace?std;

bool?is_lucky_num?(string?s)

{

string?s_rev?=?s;

reverse(s_rev.begin(),?s_rev.end());

if?(s_rev?==?s)

return?true;

return?false;

}

int?main()

{

string?s;

cin>>s;

if?(is_lucky_num(s))

cout<<"yes"<<endl;

else

cout<<"no"<<endl;

return?0;

}

g++編譯通過，望采納～