思路;分別計奇數的和，偶數的和再相減
/***VC6**C語言***/#include?<stdio.h>
int?jia(int?m);
int?jian(int?n);
int?main()
{
int?a,b;
a=jia(100);
b=jian(100);
printf("%d,%d\n",a,b);
printf("%d\n",a-b);
return?0;
}
int?jia(int?m)
{
int?sum=0;
for(int?i=1;i<=m;i+=2)
{
sum+=i;
}
return?sum;
}
int?jian(int?n)
{
int?sum=0;
for(int?i=2;i<=n;i+=2)
{
sum+=i;
}
return?sum;
}