int isPalin(int n){
char a[20],i=0,j;
while(n > 0){
a[i] = n % 10;
n = n / 10;
i++;
}
i--;
for(j=0;j<(i+1)/2;j++)
if(a[j] != a[i-j])
return 0;
return 1;
}
void main() {
unsigned int i,m,n;
printf("請輸入m和n的值:\n");
scanf("%d%d",&m,&n);
for(i=m;i<=n;i++)
if(isPalin(i)) printf("%d ",i);
}