通道1:=AA*N/100;
通道2:=AA*(200-N)/100;
CC:=ABS((2*CLOSE+HIGH+LOW)/4-MA(CLOSE,20))/MA(CLOSE,20);
DD:=DMA(CLOSE,CC);
通道3:=(1+M/100)*DD;
通道4:=(1-M/100)*DD;
L<通道2 AND C>O;