當前位置:編程學習大全網 - 網站源碼 - 大家早上好,請教個問題,以下是網易郵箱POP3接收郵件的內容,請問用C#如何將內容解碼?

大家早上好,請教個問題,以下是網易郵箱POP3接收郵件的內容,請問用C#如何將內容解碼?

+OK 916 octetsReceived: from pc (unknown [110.244.245.88]) by smtp4 (Coremail) with SMTP id DtGowEBpTloibZpT37bXAA--.1667S3; Fri, 13 Jun 2014 11:16:52 +0800 (CST)MIME-Version: 1.0From: username@163.comTo: username@163.comDate: 13 Jun 2014 11:16:24 +0800Subject: =?utf-8?B?U01UUOWuouaIt+err+WPkemAgemCruS7tua1i+ivle+8jOmd?= =?utf-8?B?nuWeg+WcvumCruS7tu+8jOa1i+ivlemAmui/h+WNs+WIoOmZpA==?=Content-Type: text/plain; charset=utf-8Content-Transfer-Encoding: base64X-CM-TRANSID:DtGowEBpTloibZpT37bXAA--.1667S3X-Coremail-Antispam: 1Uf129KBjDUn29KB7ZKAUJUUUUU529EdanIXcx71UUUUU7v73 VFW2AGmfu7bjvjm3AaLaJ3UbIYCTnIWIevJa73UjIFyTuYvj4RXEfoUUUUUX-Originating-IP: [118.244.254.90]Message-Id: <539A6D24.1AB78F.28883@m50-134.163.com>X-CM-SenderInfo: hjdr6xphdeuvi6rwjhhfrp/1tbiLx+pdFEAMa0YtgAAsOU01UUOWuouaIt+err+WPkemAgemCruS7tua1i+ivle+8jOmdnuWeg+WcvumCruS7tu+8jOa1i+ivlemAmui/h+WNs+WIoOmZpA==

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