#include "stdio.h"
#include "math.h"
void main(void){
double x,sum=0.0;
int i;
for(i=1;i<101;i++)
sum+=log10(i);
printf("%f\n",sum);
x=sum+log(3)/log(2)+log10(7)-log(105)-log10(2)*log10(7);
}
這代碼求出了log1+log2+log3+...+log100的值。而x=sum+log(3)/log(2)+log10(7)-log(105)-log10(2)*log10(7);進行了常用對數(log10)和自然對數(log)的四則運算,並計算結果賦給了雙精度變量x。