急.PHP高手進來!分全給妳

把select * from student裏的student改成數據庫裏學生信息對應的表名

把where id = 中的id改成數據庫裏面對應學號的字段名

把$row['name']和$row['class']裏的name和class也對應的改掉就可以用了

文件內容：

<?

if(isset($_POST["submited"]))

{

$student_no = $_POST["s_no"];

$sql = "select * from student where id = $student_no";

mysql_connect('localhost','php','php');

mysql_select_db('php_kaoshi');

$query = mysql_query($sql);

$row = mysql_fetch_row($query);

echo "姓名：${row['name']} <br /> 學號：$student_no <br /> 班級： ${row['class']}";

}

else

{

<form action="GetFen.php" method="post">

<input type="hidden" name="submited" value="1" />

<input name="s_no" type="text" /><button type="submit">查詢</button>

</form>

<?php

}