求簡單的python運算代碼

首先,妳看,這裏它重復提示妳輸入0或1(代表no 或 yes),所以得有壹個while循環來接收輸入是否繼續的命令:

#?coding:?utf8

while?True:

commd?=?raw_input('Would?you?like?to?play?again?(0?-?no,?1?-?yes):?')

if?str(commd).isdigit():

if?int(commd)?==?1:

print?'yes'

elif?int(commd)?==?0:

print?'Thanks?for?using?this?calculator.'

break

else:

print?'input?0?or?1!'

else:

print?'input?a?number!'