求PHP接收表單內容並發送郵件的代碼

<?

class Jmail

{

public $Username; //郵局用戶名

public $Password; //密碼

public $FormName ; //發件人姓名

public $From ; //發件人地址

public $Addrecipient ; //收件人地址

public $Ttile ; //郵件標題

public $Content; //郵件內容

public $Smtp; //郵件服務器

function Send(){

$Jmail = new com("Jmail.Message"); //實例化壹個Jmail對象

$Jmail->SiLent=true; //設置成True的話Jmail不會提示錯誤只會返回True和False

$Jmail->LogGing = false; //是否開啟日誌

$Jmail->CharSet = "GB2312"; //設定字符串編碼

$Jmail->ContentType = "Text/html"; //郵件的格式為HTML格式

$Jmail->MailServerUsername = $this->Username; //發信箱用戶名

$Jmail->MailServerPassword = $this->Password; //發信箱密碼

$Jmail->FromName = $this->FromName; //發件人姓名

$Jmail->From = $this->From; //發件人地址

$Jmail->AddRecipient($this->Addrecipient); //收件人地址

$Jmail->Subject = $this->Title;//Email標題

$Jmail->Body = $this->Content; //Email正文

$JmailError = $Jmail->Send($this->Smtp); //Smtp服務器

if($JmailError){ //判斷郵件是否發送成功

return true;

}else{

return false;

}

}

}

//這裏是調用代碼

$jmail = new Jmail();

$jmail->Username = "lwf0757";

$jmail->Password = "0757";

$jmail->FromName = "梁";

$jmail->From = "lwf0757@163.com";

$jmail->Addrecipient = "313120799@qq.com";

$jmail->Title = "這是標題";

$jmail->Content = $_POST["contact_message"]; //"這是內容";

$jmail->Smtp = "smtp.163.com";

if($jmail->Send()){

echo "成功哦!";

}else{

echo "失敗哦!";

}