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求壹份由32*16的led點陣屏 AT89C51控制的protues仿真圖及程序 謝謝

#include<reg51.h>

unsigned ?char ?code ?P2H[]={ ?0x10,0x20,0x40,0x80 };?

unsigned ?char ?code ?P2L[]={ ?0x00,0x01,0x02,0x03,0x04,0x05,0x06,0x07 };?

int a,b,n,i,j,k,t;

unsigned ?char ?code ?ziku[]={ //字符碼的存放格式為:從左到右***16列,並按列的上下部分依次存放

//壹組即為壹列

/* EL */

0x08,0x20, ?0xF8,0x3F, ?0x88,0x20, ?0x88,0x20, ?0xE8,0x23, ?0x08,0x20, ?0x10,0x18, ?0x00,0x00, ?

0x08,0x20, ?0xF8,0x3F, ?0x08,0x20, ?0x00,0x20, 0x00,0x20, 0x00,0x20, ?0x00,0x30, 0x00,0x00,

/* Va */

0x08,0x00, ?0x78,0x00, ?0x88,0x07, ?0x00,0x38, ?0x00,0x0E, ?0xC8,0x01, ?0x38,0x00, ?0x08,0x00,

0x00,0x00, ?0x00,0x18, ?0x80,0x24, ?0x80,0x22, 0x80,0x22, 0x80,0x22, ?0x00,0x3F, 0x00,0x20,

/* 秦 */ ?

0x20,0x82, ?0x20,0x82, ?0x2A,0x45, ?0x2A,0x45, ?0xAA,0x25, ?0x6A,0x15, ?0x3E,0x0D, ?0x2B,0xFF,

0xAA,0x04, ?0xAA,0x0C, ?0xEA,0x14, ?0xAA,0x24, ?0x2A,0x65, ?0x22,0xC2, ?0x20,0x42, ?0x00,0x00,

/* 波 */ ?

0x10,0x04, ?0x60,0x04, ?0x01,0xFF, ?0x16,0x40, ?0x00,0x30, ?0xF8,0x8F, ?0x88,0x80, ?0x88,0x41,

0x88,0x26, ?0xFF,0x18, ?0x88,0x18, ?0x88,0x26, ?0x88,0x61, ?0x18,0xC0, ?0x08,0x40, ?0x00,0x00,

/* , */

0x00,0x00, ?0x00,0x00, ?0x00,0x00, ?0x00,0x00, ?0x00,0x00, ?0x00,0x00, ?0x00,0x00, ?0x00,0x80, ?

0x00,0xB0, ?0x00,0x70, ?0x00,0x00, ?0x00,0x00, 0x00,0x00, 0x00,0x00, ?0x00,0x00, 0x00,0x00,

/* 自 */

0x00,0x00, ?0x00,0x00, ?0x00,0x00, ?0xF8,0x7F, ?0x48,0x24, ?0x4C,0x24, ?0x4A,0x24, ?0x48,0x24,?

0x48,0x24, ?0x48,0x24, ?0x48,0x24, ?0xF8,0x7F, ?0x00,0x00, ?0x00,0x00, ?0x00,0x00, ?0x00,0x00,

/* 動 */

0x00,0x00, ?0x40,0x08, ?0x48,0x1C, ?0x48,0x0A, ?0xC8,0x09, ?0x48,0x08, ?0x48,0x4E, ?0x40,0x28, ?

0x20,0x10, ?0x20,0x0C, ?0xFE,0x03, ?0x20,0x20, ?0x20,0x40, ?0xF0,0x3F, ?0x20,0x00, ?0x00,0x00,

/* 化 */

0x00,0x00, ?0x00,0x01, ?0x80,0x00, ?0x40,0x00, ?0xF0,0x7F, ?0x0E,0x00, ?0x00,0x04, ?0x00,0x04,

0x00,0x02, ?0xFE,0x3F, ?0x80,0x40, ?0x40,0x40, ?0x20,0x40, ?0x10,0x40, ?0x00,0x78, ?0x00,0x00,

/* 04 */

0x00,0x00, ?0xE0,0x0f, ?0x10,0x10, ?0x08,0x20, ?0x08,0x20, ?0x10,0x10, ?0xE0,0x0F, ?0x00,0x00,

0x00,0x00, ?0x00,0x07, ?0xC0,0x04, ?0x20,0x24, ?0x10,0x24, ?0xF8,0x3F, ?0x00,0x24, ?0x00,0x00,

/* 1 */

0x00,0x00, ?0x00,0x00, ?0x00,0x00, ?0x00,0x00, ?0x00,0x00, ?0x10,0x20, ?0x10,0x20, ?0xF8,0x3F, ?

0x00,0x20, ?0x00,0x20, ?0x00,0x00, ?0x00,0x00, 0x00,0x00, 0x00,0x00, ?0x00,0x00, 0x00,0x00,

/* 班 */

0x42,0x10, ?0x42,0x10, ?0xFE,0x0F, ?0x42,0x88, ?0x42,0x48, ?0xE0,0x20, ?0x00,0x18, ?0xFF,0x07, ?

0x00,0x20, ?0x42,0x20, ?0x42,0x20, ?0xFE,0x3F, 0x42,0x20, 0x42,0x20, ?0x42,0x20, 0x00,0x00,

/* . */

0x00,0x00, ?0x00,0x00, ?0x00,0x00, ?0x00,0x00, ?0x00,0x00, ?0x00,0x00, ?0x00,0x00, ?0x00,0x00, ?

0x00,0x30, ?0x00,0x30, ?0x00,0x00, ?0x00,0x00, 0x00,0x00, 0x00,0x00, ?0x00,0x00, 0x00,0x00,

};

void ? delay(int t)

{

?for(t;t>0;t--);

}

void ?show()

{

for(n=0;n<384;n+=2) //***六個字

{

for(k=0;k<10;k++) //每個字顯示的時間

{

? for(i=0;i<4;i++) //4個字符區

{ ?

for(j=0;j<8;j++) //8列

{

a=j+i*8+n;

b=j+i*8+n+32;

P2=P2H[i]+P2L[j]; ? //位選端

if(a>383)?

P0=ziku[a-384];

else ?

P0=ziku[a];

if(b>383)?

P1=ziku[b-384]; ?

else ?

P1=ziku[b];

? delay(10); //80~110

}

}

}

}

}

void main()

{

while(1)

{

show();

}

}

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