#定義N 4
#定義M 5
void main()
{
int a[N][M],I,j,k,n1,n2,n3,n4;
printf("請輸入:");printf(" \ n ");
for(I = 0;我& ltn;i++)for(j = 0;j & ltm;j++)
{scanf("%d ",& ampa[I][j]);}
for(I = 0;我& ltn;i++)/////////
for(j = 0;j & ltm;j++)////需要循環判斷。
{
//如果(i=0)
如果(i==0)
{
for(k = 1;k & ltm;k++)
{ a[I][j]+= a[I][j+k];}
n 1 = a[I][j];
for(k = 1;k & ltm;k++)
{ a[I][j]-= a[I][j+k];}
}
//else if(i=N-1)
如果(i==N-1)
{
for(k = 1;k & ltm;k++)
{ a[I][j]+= a[I][j+k];}
N2 = a[I][j];
for(k = 1;k & ltm;k++)
{ a[I][j]-= a[I][j+k];}
}
//如果(j=0)
如果(j==0)
{
for(k = 1;k & ltn;k++)
{ a[I][j]+= a[I+k][j];}
n3 = a[I][j];
for(k = 1;k & ltn;k++)
{ a[I][j]-= a[I+k][j];}
}
//else if(j=M-1)
Else if(j==M-1)// Yes = =,no =
{
for(k = 1;k & ltn;k++)
{ a[I][j]+= a[I+k][j];}
n4 = a[I][j];
for(k = 1;k & ltn;k++)
{ a[I][j]-= a[I+k][j];}
}
}
printf("%d ",n 1+N2+n3+n4);
}