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匯編語言編程:有30個數存放在MARK開始的單元,編程將其最高分和最低分取出,分別送HIGH和LOW單元,並且顯

data segment

mark db 30 dup (0)

hig db 0

lo db 0

data ends

stack segment stack

db 20 dup (0)

stack ends

code segment

assume cs:code,ss:stack

start:

mov ax,data

mov ds,ax

lea bx,mark

mov ah,[bx]

mov al,[bx]

mov si,1

goon:

cmp si,30

jnb over1

cmp ah,[bx+si]

jnb over2

mov ah,[bx+si]

over2:

cmp al,[bx+si]

jna over3

mov al,[bx+si]

over3:

inc si

jmp goon

over1:

mov hig,ah

mov lo,al ;取出最大和最小送入hig和lo

mov ah,0

call htod ;顯示最小數

mov dl,' '

mov ah,2

int 21h ;空格

mov al,hig

mov ah,0

call htod ;顯示最大數

mov ax,4c00h

int 21h

htod: ;子程序:以十進制顯示AL的數值

push bx

push cx

push dx

mov cl,0

goon2:

mov dx,0

mov bx,10

div bx

add dl,30h

push dx

inc cl

cmp ax,10

jna over4

jmp goon2

over4:

add al,30h

push ax

inc cl

goon3:

cmp cl,0

je over5

pop dx

mov ah,2

int 21h

dec cl

jmp goon3

over5:

pop dx

pop cx

pop bx

ret

code ends

end start

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