//已知abc+cba=1333,通過編程求解A、B、C所有滿足條件的組合。
void main()
{
int a,b,c;
int sum0,sum1,sum2
for(a = 0;a & lt10;a++)
{
for(b = 0;b & lt10;b++)
{
for(c = 0;c & lt10;c++)
{
sum 1 = 100 * a+10 * b+ c;
sum 2 = 100 * c+10 * b+ a;
sum 0 = sum 1+sum 2;
if(sum0 == 1333)
{
cout & lt& lt" a = " & lt& lta & lt& lt“,b = " & lt& ltb & lt& lt“,c = " & lt& ltc & lt& lt\ t ' & lt& ltsum 1 & lt;& lt+' & lt;& ltsum2 & lt& lt" = 1333 " & lt;& ltendl
}
}
}
}
}
輸出:
a=4,b=1,c = 9 419+914 = 1333
a=5,b=1,c = 8 518+815 = 1333
a=6,b=1,c = 7 617+716 = 1333
a=7,b=1,c = 6 716+617 = 1333
a=8,b=1,c = 5 815+518 = 1333
a=9,b=1,c = 4 914+419 = 1333
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